unix:bash
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unix:bash [2010/02/22 08:29] ben created |
unix:bash [2011/03/15 16:56] (current) ben |
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| - | ===== Add file sizes together from a list returned via Find ===== | + | ====== Bash Notes ====== |
| - | <code> | + | |
| - | IFS=$'\n';set j=0;for i in $(du -s $(find ./ -name \*.MOV)|cut -f 1);do j=$(( $i + j ));echo $j;done;IFS=$' \t\n' | + | |
| - | </code> | + | |
| - | This seems to keep growing after multiple runs, so something is odd. | + | <tab>**[[unix:bash:simple_arithmetic|Some simple math with file sizes]]** |
| - | Better: | + | <tab>**[[unix:bash:rss|an attempt at an rss reader for a specific purpose]]** |
| - | <code> | + | |
| - | IFS=$'\n';set j=0;for i in $(du -s $(find ./ -name \*.MOV)|cut -f 1);do j=$(( $i + j ));echo $j;done;unset i;unset j;IFS=$' \t\n' | + | |
| - | </code> | + | |
| - | Need to divide number by 2 on a Mac for human readable size in Megabytes: | ||
| - | <code> | ||
| - | IFS=$'\n';set j=0;for i in $(du -s $(find ./ -name \*.MOV)|cut -f 1);do j=$(( $i + j ));echo $(( j / 2 ));done;unset i;unset j;IFS=$' \t\n' | ||
| - | </code> | ||
| - | Better: | ||
| - | <code> | ||
| - | IFS=$'\n';set j=0;for i in $(du -s $(find ./ -name \*.MOV)|cut -f 1);do echo $i;j=$(( $i + j ));echo $j;done;echo $(( $j / 2));unset i;unset j;IFS=$' \t\n' | ||
| - | </code> | ||
| - | |||
| - | Now need to change so the file names are one var, the size is another var, so the output can be nice and neat: | ||
| - | <code> | ||
| - | IFS=$'\n';set j=0;for f in $(find ./ -name \*.MOV);do i=$(du -s $f|cut -f 1);k=$j;j=$(( $i + j ));echo $f is $(( $i / 2)) Mbytes;echo Added to $(( $k / 2 )) Mbytes equals $(( $j / 2 ));done;unset f;unset i;unset j;unset k;IFS=$' \t\n' | ||
| - | </code> | ||
| - | |||
| - | This seems to be the working but quite verbose code (important to note "k / 2" instead of "$k / 2", apparently caused by the set of k=$j, creates a pointer or something?): | ||
| - | <code> | ||
| - | IFS=$'\n';set j=0;set k=0;set i=0;set f=;for f in $(find ./ -name \*.MOV);do i=$(du -s $f|cut -f 1);k=$j;j=$(( $i + j ));echo $f is $(( $i / 2)) Mbytes;echo Added to $(( k / 2 )) Mbytes equals $(( $j / 2 )) Mbytes;done;echo The total size is $(( $j /2 )) Mbytes;unset f;unset i;unset j;unset k;IFS=$' \t\n' | ||
| - | </code> | ||
| - | |||
| - | Now, can we get it sorted? | ||
unix/bash.1266845356.txt.gz · Last modified: 2010/02/22 08:29 by ben
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